Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
231 views
in Vectors by (59 points)
recategorized by

A= i bar +2j bar +2k bar. Calculate angle between A bar and y axis.

\(\vec A=\hat i+2\hat j+2\hat k\)

Please log in or register to answer this question.

1 Answer

0 votes
by (45.0k points)

\(\vec A=\hat i+2\hat j+2\hat k\)

Equation of  y-axis is \(\vec y=0\hat i+\hat j + 0\hat k\)

|\(\vec A\)| = \(\sqrt{1+4+4}=3\)

|\(\vec y\)| = \(\sqrt{0+1+0}=1\)

\(\vec A.\vec y=(\hat i+2\hat j+2\hat k).(0\hat i+\hat j+0\hat k)\)

⇒ |\(\vec A\)||\(\vec y\)| cos θ = 2, where θ is angle between \(\vec A\) and y - axis.

⇒ cos θ = \(\frac2{|\vec A||\vec y|}=\frac23\)

⇒ θ  = cos-1(2/3) ≈ 48.2°

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...