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in Physics by (54.5k points)

A uniform vertical tube of circular cross-section contains a liquid. The contact angle is 90°. Consider a diameter of the tube lying in the surface of the liquid. The surface to the right of this diameter pulls the surface on the left of it. What keeps the surface on the left in equilibrium?

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Let the diameter in consideration be AB as in the above figure. The surface to the right of AB pulls the surface on the left of AB (say by a total force = F) due to surface tension. The semicircular walls of the tube in contact with the surface to the left of AB also pulls it towards left with a net force F. Thus the semicircular surface ABD is pulled by two equal and opposite forces, making the net force on it zero. So it remains in equilibrium.  

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