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in Sets, Relations and Functions by (30 points)
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The set (x: (x - 2) (x - 3) > 0} is equal

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Let x = {x : (x - 2)(x -3) > 0}

∵ (x - 2)(x - 3) > 0

\(x \in(- \infty, +2 ) \cup(3, \infty)\)

\(x \in \mathbb{R} - [2, 3]\)

Hence, \(x = ( - \infty 2) \cup (3, \infty)\)

or \(x = \mathbb{R} - [2, 3]\)

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