Question

In hydrogen atom, energy of first excited state is -3·4 eV. Find out the K.E. of the same orbit of hydrogen atom

(A)  +3·4eV 

(B)  +6·8eV

(C)   –13·6eV

(D)   +13·6eV

Answer 1

Correct option (A) +3·4eV

K.E. of e^-  in nth orbit = - E_n = 3.4 e.V