(i) Since, Redfort remains close on Monday.
So, none of them visits Redfort on Monday
∴ Probability of visiting Redfort on Monday = 0.
(ii) Probability of not visiting Redfort on Monday
= 1 - Probability of visiting Redfort on Monday
= 1 - 0
= 1
(iii) They both decides the visiting day by throwing a die. If out comes of both dies are same then the visit Redfort on Same day otherwise on different day.
∴ Probability of visiting Redfort on same day = Probability that both die will give same out comes
\(=\frac{6}{36} = \frac16\)
(iv) Probability of visiting Redfort on different day = Probability that both die will give different outcomes
\(= \frac{30}{36} = \frac56\)