The value of sin^2 θ + 1 1/(1+tan^2θ) is

Question

The value of sin² θ + \(1\frac{1}{(1+tan^2θ)}\) is

(1) sin² θ

(2) cos² θ

(3) Sec² θ

(4) 1

Answer 1

 (4) 1

sin² θ + \(\frac{1}{1+tan^2\theta}\) = sin² θ + \(\frac{1}{sec^2\theta}\) = sin² θ + cos² θ = 1