Find the Derivative

Question

Please log in or register to answer this question.

+1 vote

1 answer

asked Jan 10, 2023 in Derivatives by SamMJ (50 points)

+1 vote

1 answer

asked Jun 17, 2022 in Derivatives by bryanttan277 (120 points)

+1 vote

1 answer

asked Jun 17, 2022 in Derivatives by bryanttan277 (120 points)

+1 vote

1 answer

asked Jun 17, 2022 in Derivatives by bryanttan277 (120 points)

0 votes

1 answer

asked Jun 17, 2022 in Derivatives by bryanttan277 (120 points)

SujitTiwari · Answer 1 · 2022-06-18T10:04:43+0000

\(\frac{dy}{dx} = \frac d{dx}ln(x^3 + 3x - 4)\)

\(= \frac 1{x^3 + 3x - 4}\,\,\,\frac d{dx} (x^3 + 3x - 4)\)

\(= \frac{3x^2 + 3}{x^3 + 3x - 4}\)