Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
95 views
in Derivatives by (120 points)
retagged by

Find the derivative:

y = 5xsinx

Please log in or register to answer this question.

1 Answer

0 votes
by (48.5k points)

\(\frac{dy}{dx} = \frac{d}{dx}5x^3 sin \, x\)

\(=5x^3 \frac d{dx}sin\,x+ \left(\frac{d}{dx}5x^3\right)sin\,x\)

\(= 5x^3 cos x + 15 x^2 sin x\)

\(= 5x^2 (x\, cos x+ 3 sinx)\)

Related questions

+1 vote
1 answer
+1 vote
1 answer
asked Jun 17, 2022 in Derivatives by bryanttan277 (120 points)
+1 vote
1 answer
asked Jun 17, 2022 in Derivatives by bryanttan277 (120 points)
+1 vote
1 answer
asked Jun 17, 2022 in Derivatives by bryanttan277 (120 points)
0 votes
1 answer
asked Jun 17, 2022 in Derivatives by bryanttan277 (120 points)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...