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Evaluate the indefinite integral

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Evaluate the indefinite integral:

∫6x5-18x2+7 dx

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1 Answer

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\(\int (6x^5 -18x^2 + 7)dx\)

\(= 6\int x^5 dx - 18\int x^2 dx + 7\int dx\)

\(= 6\left(\frac{x^6}{6}\right)-18\left(\frac{x^3}3\right) + 7x + C\)

\(= x^6 - 6x^3 + 7x + C\)

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