Question

Find the equation of the polar of the point (2, –1) with respect to the circle x² + y² – 3x + 4y – 8 = 0 

Answer 1

Given circle is x² + y² – 3x + 4y – 8 = 0 ............(i) 

Given point is (2, –1) let P = (2, –1). 

Now equation of the polar of point P with respect to circle (i)

or 4x – 2y – 3x – 6 + 4y – 4 – 16 = 0 

or x + 2y – 26 = 0