Question

The radii of two pistons in a hydraulic press are 4 cm and 16 cm respectively. A force of \( 25 N \) is applied to the smaller piston. Find the force exerted on the larger piston.

Answer 1

P₁ = P₂

_{\(\cfrac{F_1}{\pi{r^2}}=\cfrac{F_2}{\pi{r}2}\)}

_{\(\cfrac{25}{(0.04)^2}=\cfrac{F^2}{(0.16)^2}\)}

F₂ = \(\frac{25\times(0.16)^2}{(0.04)^2}\)

F₂ = \(\frac{0.64}{0.0016}\)

F₂ = 400N