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The difference between DH and DE on a molar basis for the combustion of n–octane at 25°C would be : 25ºC

(A)   – 13.6 kJ

(B)  – 1.14 kJ

(C)  – 11.15 kJ

(D)  + 11.15 kJ 

1 Answer

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Best answer

Correct option (C) – 11.15 kJ

Explanation:

ΔH – ΔE = – 4.5 × 8.315 × 298 J

= – 11.15 kJ

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