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यदि a = \(\frac{\sqrt5+1}{\sqrt5-1}\) व b = \(\frac{\sqrt5-1}{\sqrt5+1}\), तब सिद्ध कीजिये कि \(\frac{a^2+ab+b^2}{a^2-ab+b^2}=\frac43\)

(a2 + ab + b2)/(a2-ab + b2

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\(\therefore\) L.H.S. \(\frac{a^2+ab+b^2}{a^2-ab+b^2}=\frac86=\frac43\) = R.H.S.

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