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एक समान्तर श्रेणी के 5 वें तथा 9 वें पदों का योग 30 है। यदि इसका 25 वाँ पद, इसके 8 वें पद का तीन गुना है तो समान्तर श्रेणी ज्ञात कीजिए।

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माना श्रेणी का प्रथम पद a तथा सार्वअन्तर d है।

∵ a5 + a9 = 30

⇒ a + 4d + a + 8d = 30

⇒ 2a + 12d = 30

⇒ a + 6d = 15 …(1)

दिया है., a25 = 3 × a8

⇒ a + 24d = 3 × (a + 7d)

⇒ a + 24d = 3a + 21d

⇒ a = 3d/2 …(2)

समीकरण (2) से a का मान समीकरण (1) में रखने पर

3d/2 + 6d = 15

⇒ 3d + 12d = 15 × 2

⇒ 15d = 15 × 2

⇒ 15d = 30

⇒ d = 2

तथा a = 3

अतः श्रेणी 3, 5, 7, 9….

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