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101 तथा 999 के बीच की प्राकृतिक संख्याओं की संख्या ज्ञात कीजिए, जोकि 2 तथा 5 दोनों के द्वारा विभाजित हैं।

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∵ 101 तथा 999 के बीच प्राकृतिक संख्यायें जोकि 2 तथा 5 दोनों के द्वारा विभाजित हैं।

∴ 110, 120, 130, …, 990

तब a= 110 तथा d = 120 – 110 = 10 तथा अन्तिम पद l = 990

l = a + (n – 1)d

990 = 110 + (n – 1) × 10

990 – 110 = (n – 1) × 10

880 = (n – 1) × 10

⇒ 880/10 = n – 1

88 = n – 1

88 + 1 = n या n = 89

अत: 101 तथा 999 के बीच प्राकृतिक संख्याओं की संख्या जो 2

तथा 5 दोनों के द्वारा विभाजित हैं = 89

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