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how many oxygen atoms present in 18 gram of CO2

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1 mol of CO2 = 12 + 32 = 44g

Number of oxygen in 1 molecule of CO2 = 2

Therefore, 

44g of CO2 contains 2 mol of oxygen 

18g of CO2 contains = 2/44 × 18 = 0.81 mol of oxygen 

1 mil = 6.022 × 10²³ atoms

0.81 mol = 4.877 × 10²³atoms




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