how many oxygen atoms present in 18 gram of CO2

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subham2847 · Answer 1 · 2022-06-26T06:12:44+0000

1 mol of CO2 = 12 + 32 = 44g

Number of oxygen in 1 molecule of CO2 = 2

Therefore,

44g of CO2 contains 2 mol of oxygen

18g of CO2 contains = 2/44 × 18 = 0.81 mol of oxygen

1 mil = 6.022 × 10²³ atoms

0.81 mol = 4.877 × 10²³atoms