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in Mathematics by (76.5k points)

Show by using distance formula that the points (4, 5, –5), (0, –11, 3) and (2, –3, –1) are collinear.

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Let A ≡ (4, 5, –5), B ≡ (0, –11, 3), C ≡ (2, –3, –1).

BC + AC = AB 

Hence points A, B, C are collinear and C lies between A and B

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