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यदि बिन्दु (a, 0), (1, – 1) व (11, 4) सरेख हैं तब a का मान ज्ञात कीजिए।

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∆ का क्षेत्रफल = 1/2[(-a + 4 + 0) – (0 – 11 + 4a)]

0 = 1/2  [-a + 4 + 11 – 4a]

0 × 2 = – 5a + 15

0 = – 5a + 15 ⇒ 5a = 15

a = 15/3 = 3.

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