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in Current electricity by (15 points)
16. In order to measure the internal resistance \( r_{1} \) of a cell of emf \( E \), a meter bridge of wire resistance \( R_{0}=50 \Omega \), a resistance \( R_{0} / 2 \), another cell of emf \( E / 2 \) (internal resistance \( r \) ) and a galvanometer \( G \) are used in a circuit, as shown in the figure. If the null point is found at \( \ell=72 cm \), then the value of

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2 Answers

+1 vote
by (476 points)

check this answer .image

0 votes
by (476 points)
edited


We know that total length of meter bridge wire is 100 cm.
Given:
l=72 cm; x=100l=28 cm

Since, (l+x) has resistance of 50 Ω,

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