Question

The cartesian coordinates of a point on the parabola x² =36y ,whose parameter is 1/3.

Answer 1

Parametric equation of parabola x² = 36y is (18t, 9t²)

∵ \(t = \frac13\) given

∴ Point on parabola is \(\left(\frac{18}3,\frac99\right) = (6,1)\).

Hence, required point is (6, 1).