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If there is a biased dice with number 2, 4, 8, 16, 32, 32. Probability of appearing of number n is 1/n . Then the probability of sum 48 in 3 throws is 

1 Answer

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Best answer

Correct answer is 7/163

For sum = 48 in 3 throw , possible cases are

{8,8,32}, {16,16,16}

∴ Required probability 

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