Question

Find dy/dx, \( y=\sin \left(\log 10^{x}\right) \)

Answer 1

y = sin(log 10^x) = sin (x log 10)

\(\frac{dy}{dx}\) = cos(x log 10) \(\frac{dy}{dx}\)(x log 10) (By chain rule)

 = cos (log10^x) log 10

 = log 10 cos(log10^x)