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A car covers AB distance with first one-third at velocity v1 ms-1 second one-third at v2 ms-1 and last one-third at v3 ms-1. If V3 = 3V1, V2 = 2v1 and V1 = 11 ms-1 then the average velocity of the car is ms-1.

1 Answer

+1 vote
by (44.4k points)
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Best answer

Correct answer is 18 m/s

by (10 points)
Can someone explain why 1/3 is multiplied at the denominator
by (55.0k points)
Given in question....
by (10 points)
+1
taken common from t1=(l/3)/v1 t2= (l/3)/v2 t3=(l/3)/v3

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