Question

Let AB and PQ be two vertical poles, 160 m apart from each other. Let C be the middle point of B and Q, which are feet of these two poles. Let π/8 and θ be the angles of elevation from C to P and A, respectively. If the height of pole PQ is twice the height of pole AB, then tan² θ is equal to

(A) 3 - 2√2 / 2

(B) 3 + √2 / 2

(C) 3 - 2√2 / 4

(D) 3 - √2 / 4

Answer 1

Correct option is (C) 3 - 2√2 / 4

Let BC = CQ = x & AB = h and PQ = 2 h