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in Oscillation and Waves by (25 points)
edited by

A sound wave of frequency ( 660 Hz ) is incident normally at reflecting wall then minimum distance front wall at which particle's pressure amplitude will be maximum (velocity of sound = 330 m/s)

1) 0.215m

2) 0.125m

3) 1m

4) 0.25m

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1 Answer

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by (42.1k points)

\(V\) = 660 Hz

\(v\) = 330 m/s

\(\lambda = \frac vV = \frac{330}{660} = 0.5\)m

Thus the shortest distance b/w wall (node) and the point where the air particles have maximum amplitude of vibration (anti node) 

\(d = \frac\lambda4\)

\(d = \frac{0.5}4\)

\(d = 0.125 m\)

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