The correct option (a) [(8m3 – 6m)/2]
Explanation:
[{x + (1/x)}/2] = m ⇒ x + (1/x) = 2m
also x3 + (1/x3) = [x + (1/x)]3 – 3[x + (1/x)]
∴ mean of x3 & (1/x3) is given by
(1/2)[x3 + (1/x3)] = (1/2)[{x + (1/x)}3 – 3{x + (1/x)}]
= (1/2)[(2m)3 – 6m]
= (1/2)(8m3 – 6m).