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1 Answer

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by (15 points)

Let's Find Out Currents In The Arc Portion, Which Are In Parallel Across X and Y.

⇒ iABC = R​​​ADC = lADC = 60°

⇒iADC = RABC = lABC= 2π-60°

( Current Is Inversely Proportional To Resistance)

( Resistance Directly Proportional To Length)

(You Can Treat 60° as π/3)

( Note: 'i' is current, 'R' is Resistance, 'l' is Length)

Therefore, iABC = i × 60°/2π

iADC = i(2π-60°)/2π

BABC= Magnetic field due to arc portion ABC

= µº(i× 60°/2π)(2π-60°)/ 4πr

= µ°i×60°(2π-60°)/8π²r

Similarly, BADC= Magnetic Field Due To Arc ADC

= µ°[i(2π-60°)/2π]× 60°/4πr

= µ°i×60°(2π-60°)/8π²r 

B1= BABC, B2= BADC 

Hence B1/B2= 1

(Please Try To Formulate The Solution By Yourself In Notebook And Understand The Concept Because I Faced Some Problems In Writing It Properly.... Good Luck For Your Studies.......)

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