The correct option (a) 3
Explanation:
m observation have value = b and m have value = – b.
∴ Mean = [{bm + (– b)m}/2m] = 0
i.e. x = 0
Standard deviation = √[{∑(xi – x)2}/2n]
∴ 3 = √[{(b – 0)2 + (b – 0)2 + ----- (0 – b)2 + (0 – b)2 + -----}/2n]
∴ 3 = √[{b2 ∙ (2n)}/2n]
∴ |b| = 3.