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A capacitor of capacitance C can be charged (with the help of a resistance R) by a voltage source V, by closing switch S1 while keeping switch S2 open. The capacitor can be connected in series with an inductor ‘L’ by closing switch S2 and opening S1.

After the capacitor gets fully charged, S1 is opened and S2 is closed so that the inductor is connected in series with the capacitor. Then, 

(A) At t = 0, energy stored in the circuit is purely in the form of magnetic energy. 

(B) At any time t > 0, current in the circuit is in the same direction. 

(C) At t > 0, there is no exchange of energy between the inductor and capacitor. 

(D) At any time t > 0, instantaneous current in the circuit is \(V\sqrt\frac CL\)

1 Answer

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Best answer

Correct option is (D) At any time t > 0, instantaneous current in the circuit is \(V\sqrt\frac CL\) 

Now when S1 is opened and S2 is closed

At t = 0; energy stored is purely in capacitor. In this type of circuits, charge and current will be in the form of sin or cos. Thus oscillatory.

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