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एक 45° के ∠BAC की रचना कीजिए। इसके अंतः क्षेत्र में बिन्दु P से रेखी खंड BA और AC पर लम्ब PN और PM खींचिए। ∠NPM का मान । ज्ञात कीजिए।

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∠BAC + ∠PNA + ∠NPM + ∠PMA = 360°

⇒ 45° + 90° + ∠NPM + 90° = 360°

⇒ ∠NPM = 360° – 225°

⇒ ∠NPM = 135°

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