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समान्तर चतुर्भुज की किसी भुजा पर बने कोणों में 40° का अन्तर है। प्रत्येक कोण का माने ज्ञात कीजिए।

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माना समान्तर चतुर्भुज की भुजा पर बना एक कोण = x°

अतः समान्तर चतुर्भुज की भुजा पर बना दूसरा कोण = 40° + x°

⇒ x° + x° + (40° + x°) + (40° + x°) = 360°

⇒ 4x° + 80° = 360°

⇒ 4x° = 360° – 80° = 280°

⇒ x° = 280°/4 = 70°

अतः समान्तर चतुर्भुज की भुजा पर बना दूसरा कोण = 40° + 70° = 110°

अतः प्रत्येक कोण = 70°, 110°, 70°, 110°

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