(B) Ionization as well as geometrical isomerism
[pt(NH3)4Cl2]Br2 and [pt(NH3)4 Br2]Cl2 are ionization isomer.
∵ [pt(NH3)4Cl2]Br2 can form Cu & trans isomer, therefore it shows geometrical isomerism.
Both as and trans is omen have plane of symmetry because of that they can not show optical isomerism.
And in [pt(NH3)4Cl2]Br2 , there is no ambidentate ligand so that if can not show linkage isomerism.
Hence, [pt(NH3)4Cl2]Br2 , shows only ionization as well as geometrical isomerism.