Correct option (b) 6.25 m
Explanation:
mass of NaOH in 500 gm 25% W/W NaOH solution
= 5 x 25 = 125 gm. and
mass of H2O = 5 x 75 = 375 gm.
mass of NaOH in 500 gm 15% W/W NaOH = 5 x 15 = 75 gm.
and mass of H2O = 5 x 85 = 425 gm.
mass of NaOH in a mixed solution when both solutions are mixed W = 125 + 75 = 200 gm.
and mass of H2O w0 = 375 + 425 = 800 gm.
Now molality of mixed solution = 1000 x w/M x W0 = 1000 x 200/48 x 800 = 6.25 m