-> Will consider potential divider to calculate voltage at Nodes B & D,
-> voltage at B = Vx2/(4+2)=20x2/(4+2)=40/6 V
-> voltage at D = Vx4/(8+4)=20x4/(8+4)=80/12 V = 40/6 V
-> Current through resistor BD path = (Vb-Vd)/R= (0)/10
= Zero is the answer