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in Physics and measurements by (15 points)
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A particle passes a point at the instant \( t=0 s \), moving with uniform velocity \( 2 \sqrt{3} m / s \) in the direction. It turns towards east at the instant \( t=8 s \) and moves with uniform velocity \( 6 m / s \). Directic change in its velocity vector is 

(A) \( 30^{\circ} \) east of north 

(B) \( 60^{\circ} \) south of east 

(C) \( 60^{\circ} \) east of north 

(D) \( 30^{\circ} \) south of east

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1 Answer

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\(tan\theta = \frac{2\sqrt3}6\)

\(tan\theta = \frac{\sqrt3}3\)

\(tan\theta = \frac1{\sqrt3}\)

\(\theta = tan^{-1}\left(\frac1{\sqrt3}\right)\)

\(\theta = 30° \) south of east

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