Question

Time period of simple pendulum is measured to be T = (2.5 ± 0.1) s, then percentage error in measurement is 

a) 2% 

b) 4% 

c) 1% 

d) 2.5%
 

Answer 1

Correct option is b) 4%

Given

T = (2.5 \(\pm\) 0.1)

Then T = 2.5,  ΔT = 0.1

So

Percentage error = \(\frac{\Delta T}T \times 100\)

\(= \frac{0.1}{2.5} \times 100\)

\(= \frac{100}{25}\)

\(= 4\)%