The correct option (c) (4/7)
Explanation:
P(i) ∝ i and i = 1 to 6
∑P(i) = 1
∴ ∑Ki = 1
∴ K∑i = 1
∴ K(1 + 2 + 3 + 4 + 5 + 6) = 1
∴ K = (1/21)
P(even number on dice) = P(A)
∴ P(A) = P(2) + P(4) + P(6) = 2K + 4K + 6K = 12K
∴ P(A) = 12 × (1/21) = (12/21) = (4/7).