Question

Correct decreasing order of energy of the orbitals having following set of quantum numbers

A) n = 3, l = 0, m = 0

B) n = 4, l = 0, m = 0

C) n = 3, l = 1, m = 0

D) n = 3, l = 2, m = 1

(a) A > C > B > D

(b) D > B > C > A

(c) A > B > C > D

(d) D > C > B > A

Answer 1

(b) D > B > C > A

Following the principle of (n+1) rule, the correct order of energy is D > B > C >
A

The subshells with the lowest (n+1) value has the lowest energy. When two or more subshells have the same (n+1) value, then the subshell with the lowest value of n have lowest energy