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Efficiency of a Carnot engine is 50%. If the temperature of the sink is decreased by 40°C, keeping the temperature of the source constant, then its efficiency becomes 80%. Find the temperature of the source: 

(1) \(\frac{200}{3}\) K

(2) \(\frac{400}3 \) K

(3) 200 K 

(4) 400 K

1 Answer

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Best answer

Correct option is (2) \(\frac{400}3 \) K

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