Let the equation of two diameters of a circle x^2 + y^2 –2x + 2fy + 1 = 0 be 2px – y = 1 and 2x + py = 4p. - Sarthaks eConnect

Let the equation of two diameters of a circle x² + y² –2x + 2fy + 1 = 0 be 2px – y = 1 and 2x + py = 4p. Then the slope m ∈ (0, ∞) of the tangent to the hyperbola 3x² – y² = 3 passing through the centre of the circle is equal to _______.

Let the equation of two diameters of a circle x^2 + y^2 –2x + 2fy + 1 = 0 be 2px – y = 1 and 2x + py = 4p.

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