Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.2k views
in Kinematics by (15 points)
The position co-ordinates of a particle moving in a 3-D coordinate system is given by \( x=a \cos \omega t ; y=a \sin \omega t \) and \( z=a \omega t \) The speed of the particle is: [JEE (Main) 2019; 4/120, (1) \( \sqrt{3} a \omega \) (2) \( 2 a \omega \) (3) \( \sqrt{2} a \omega \) (4) \( a \omega \)

Please log in or register to answer this question.

1 Answer

0 votes
by (24.8k points)

Answer: \((3)\,\sqrt2a\omega\)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...