120. Let \( a_{1}, a_{2}, a_{3}, \ldots \) be an A.P. If \( \frac{a_{1}+a_{2}+\ldots+a_{10}}{a_{1}+a_{2}+\ldots+a_{p}}=\frac{100}{p^{2}}, p \neq 10 \), then \( \frac{a_{11}}{a_{10}} \) is equal to
[JEE (Main)-2021]
(1) \( \frac{19}{21} \)
(2) \( \frac{100}{121} \)
(3) \( \frac{21}{19} \)
(4) \( \frac{121}{100} \)
