Question

The value printed by the following program is ______.

void f(int* p, int m){ 

m = m + 5; 

*p = *p + m; 

return;

}

void main(){ 

int i = 5, j = 10;

f(&i, j);

printf("%d", i+j);

}

Answer 1

Correct answer is 30

i ’s address and j ’s value are passed to the function of f. f modifies i value to 20. j value remains same (as its value is passed not the reference). 

∴ i + j = 30 will be printed