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A network has a data transmission bandwidth of 20 x 106 bits per second. It uses CSMA/CD in the MAC layer. The maximum signal propagation time from one node to another node is 40 microseconds. The minimum size of a frame in the network is ______ bytes.

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Correct answer is 200

B = 2 x 106 bps

Tp = 40µs

L= ?

L = 2 x Tp x B ⇒ L= 2 x 40 x 10-6 x 20 x 10

= 1600 bits (or) 200 bytes

L = 200 bytes

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