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in Mathematics by (42.1k points)
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The equation of a common tangent to the parabolas y = x2 and y = -(x - 2)2 is

(A) y = 4(x - 2)

(B) y = 4 (x - 1)

(C) y = 4 (x + 1)

(D) y = 4 (x + 2)

1 Answer

+1 vote
by (48.4k points)
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Best answer

Correct option is (B) y = 4 (x - 1)

Equation of tangent of y = x2 be

From eq. (1), required common tangent is 

y = 4 (x - 1)

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