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Negation of the Boolean expression p ⇔ (q ⇒ p) is

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Negation of the Boolean expression p ⇔ (q ⇒ p) is

(A) (~ p) ∧ q

(B) p ∧ (~ q)

(C) (~ p) ∨ (~ q)

(D) (~ p) ∧ (~ q)

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2 Answers

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Best answer

By truth table, we can conclude that 

\(\sim(p ⇔ (q ⇒ p)) \equiv (\sim p) \wedge(2q)\)

+2 votes
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Correct option is (D) (~ p) ∧ (~ q)

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