Question

If pqr ≠ 0 and \(p^{-x}\) = 1/q, \(q^{-y}\) = 1/r,\( r^{-z}\) = 1/p, what is the value of the product xyz?

A. -1

B. 1/pqr

C. 1

D. pqr

Answer 1

Correct option is (C) -1

we get 

1/q = p^-x -------(1) 

1/r = q^-y -------(2) 

1/p = r ^-z -------(3) 

1/q = p^-x

= r^-xz [Putting value of p from (3)] 

= q^-xyz [Putting value of r from (2)] 

= 1 / q^xyz

On comparing power of q both sides, we get xyz = 1