Use app×
Ask a Question
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE

अधिष्ठापन .....

← Prev Question Next Question →
0 votes
83 views
in Mathematics by (15 points)
8+16+24+.... +8n=4n(n+1) गणितीय अधिष्ठापन
Play Quiz Game >

Please log in or register to answer this question.

1 Answer

0 votes
by (42.2k points)

\(8 + 16 + 24 + \,....+ 8n\)

\(= 8(1 + 2 + 3 + ...+ n)\)

\(= 8\frac {n(n+ 1)}{2}\)     \(\left(\because 1 + 2 + 3 + ....+ n = \frac {n(n + 1)}{2}\right)\) 

\(= 4n(n+ 1)\)

Hence proved.

← Prev Question Next Question →

Find MCQs & Mock Test

  1. JEE Main 2025 Test Series
  2. NEET Test Series
  3. Class 12 Chapterwise MCQ Test
  4. Class 11 Chapterwise Practice Test
  5. Class 10 Chapterwise MCQ Test
  6. Class 9 Chapterwise MCQ Test
  7. Class 8 Chapterwise MCQ Test
  8. Class 7 Chapterwise MCQ Test

No related questions found

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

User Contribution to Sarthaks eConnect
Managed by Sarthaks Digitizing India
...