Question

Solve the matrix equation:

If [(2x, 3)] [(1,2)(-3,0)] [x,3] = 0, then find x.

 [2x - 3] \(\begin{bmatrix}1& 2\\-3&0\end{bmatrix}\begin{bmatrix}x\\ 3\end{bmatrix}=0\)

Comments

Could get the question correctly....Add Picture of it

Answer 1

We are given, 

[2x - 3] \(\begin{bmatrix}1& 2\\-3&0\end{bmatrix}\begin{bmatrix}x\\ 3\end{bmatrix}=0\)

We know that, [aij]_m×n​ can multiply with [bij]_n×o​ So we get a product as [cij]_m×o​ here [cij] contains [m×o] entries.

The value of x will be 0 or -3/2