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A bag of sand of mass m is suspended by rope a bullet of mass (m / 30) is fired at it with a velocity V and gets embedded into it. The velocity of the bag finally is _________ 

(A) (31V / 30) 

(B) (30V / 31) 

(C) (V / 31) 

(D) (V / 30)

1 Answer

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Best answer

Correct option: (C) (V / 31)

Explanation:

m1 =(m / 30) ; V1 = V

m2 = m + (m / 30): V2 = 2

Principle of conservation of momentum.

m1V1 = m2V2 

(m / 30)(V) = {m + (m / 30)}V2 

(V / 30) = (31 / 30)V2 

V2 = (V / 31) m/s   

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